document.write( "Question 1044900: One side of a parallelogram is 10cm and its diagonals are 16m and 24cm respectively. Find its area \n" ); document.write( "
Algebra.Com's Answer #660364 by ikleyn(52778)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "One side of a parallelogram is 10cm and its diagonals are 16m and 24cm respectively. Find its area
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "1.  The area of a parallelogram is equal to half the product of its diagonals by the sine of the angle between them:\r\n" );
document.write( "\r\n" );
document.write( "    S = \"%281%2F2%29%2Ad%5B1%5D%2Ad%5B2%5D%2Asin%28delta%29\".\r\n" );
document.write( "\r\n" );
document.write( "    See the lesson Area of a parallelogram in this site.\r\n" );
document.write( "\r\n" );
document.write( "    Any of the two angles is good.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "2.  You have the diagonals, and all you need is the sine of the angle between the diagonals.\r\n" );
document.write( "\r\n" );
document.write( "    Instead of sine, we can find the cosine of the angle between the diagonals.\r\n" );
document.write( "\r\n" );
document.write( "    For it, we will use the Cosine Law by applying it to the triangle formed by halves of diagonals and the side of the parallelogram:\r\n" );
document.write( "\r\n" );
document.write( "    \"10%5E2\" = \"16%5E2+%2B+24%5E2+-+2cos%28delta%29%2A16%2A24\".\r\n" );
document.write( "\r\n" );
document.write( "    Which gives  \"cos%28delta%29\" = \"%2816%5E2%2B24%5E2-10%5E2%29%2F%282%2A16%2A24%29\" = \"732%2F768\".\r\n" );
document.write( "\r\n" );
document.write( "    And then \"sin%28delta%29\" = \"sqrt%281-cos%5E2%28delta%29%29\" = \"sqrt%281+-+%28732%2F768%29%5E2%29\" = \"sqrt%2854000%2F768%5E2%29\" = \"sqrt%283%5E2%2A6%2A10%5E3%29%2F768\" = \"sqrt%283%5E3%2A2%5E4%2A5%5E3%29%2F%282%5E8%2A3%29\" = \"%283%2A2%5E2%2A5%2Asqrt%2815%29%29%2F%282%5E8%2A3%29\" = \"%285%2Asqrt%2815%29%29%2F2%5E6\" = \"%285%2Asqrt%2815%29%29%2F64\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "4.  Finally, the area of the parallelogram is\r\n" );
document.write( "\r\n" );
document.write( "    S = \"%281%2F2%29%2A16%2A24%2A%285%2Asqrt%2815%29%29%2F64\" = \"15%2Asqrt%2815%29\" = 58.095 \"cm%5E2\" (approximately).\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Answer.  The area of the parallelogram is  \"15%2Asqrt%2815%29\" = 58.095 \"cm%5E2\" (approximately).\r\n" );
document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" );