document.write( "Question 1031092: The parameter of a triangle is 49cm the one side is 7cm longer than the other & 5cm shorter than the third side find the length of each side of triangle \n" ); document.write( "

Algebra.Com's Answer #660306 by Jolliano(16) $\"\"$ $\"About$

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Let the 3 sides be a, b and c.\r
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\n" ); document.write( "\n" ); document.write( "therefore,
\n" ); document.write( "a + b + c = 49 ...(1)
\n" ); document.write( "a = b + 7 ...(2)
\n" ); document.write( "a = c - 5 ...(3)\r
\n" ); document.write( "\n" ); document.write( "From (2),
\n" ); document.write( "a = b + 7
\n" ); document.write( "b = a - 7 ...(4)\r
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\n" ); document.write( "\n" ); document.write( "From (3),
\n" ); document.write( "a = c - 5
\n" ); document.write( "c = a + 5 ...(5)\r
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\n" ); document.write( "\n" ); document.write( "Substitute equations (4) and (5) in (1)
\n" ); document.write( "a + b + c = 49
\n" ); document.write( "a + (a - 7) + (a + 5) = 49
\n" ); document.write( "3a - 2 = 49
\n" ); document.write( "3a = 49 + 2
\n" ); document.write( "3a = 51
\n" ); document.write( "a = 51/3
\n" ); document.write( "a = 17cm\r
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\n" ); document.write( "\n" ); document.write( "Substitute the value of a in (4)
\n" ); document.write( "b = a - 7
\n" ); document.write( "b = 17 - 7
\n" ); document.write( "b = 10cm\r
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\n" ); document.write( "\n" ); document.write( "Substitute the value of a in (5)
\n" ); document.write( "c = a + 5
\n" ); document.write( "c = 17 + 5
\n" ); document.write( "c = 22cm \n" ); document.write( "

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