document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1044832>Question 1044832</A>: <I><SPAN STYLE=\"word-break: break-all;\">  (9-x^-2)/(3+x^-1) ?<BR>\n" );
document.write( "a) 3x-1/x^2<BR>\n" );
document.write( "b) 3x+1/x^2<BR>\n" );
document.write( "c) 3x+1/x<BR>\n" );
document.write( "d) x(3x-1)<BR>\n" );
document.write( "e) 3x-1/x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #660226 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=660226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is E.  Here is why.<BR>\n" );
document.write( "Write the numerator as 9-(1/x^2).  Common denominator of x^2 and get (9x^2-1)/x^2 and write it as <BR>\n" );
document.write( "(3x+1)(3x-1)/x^2, a difference of squares.  This is the numerator.<BR>\n" );
document.write( "The denominator is 3+(1/x). That is (3x+1)/x<BR>\n" );
document.write( "We cancel a (3x+1) in both and an x in both.<BR>\n" );
document.write( "That leaves (3x-1)/x, or E.<BR>\n" );
document.write( "Sometimes you want negative exponents, other times you want to write them as fractions.  Here, the latter works better. </SPAN>\n" );
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