document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1044802>Question 1044802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of ages of a woman and her son is 64years. In 4years time, the woman will be three and a half times as old as her son. How old were they 4years ago </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #660196 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=660196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=woman's age<BR>\n" );
document.write( "y=son's age<BR>\n" );
document.write( "x+y=64<BR>\n" );
document.write( "(x+4)=3.5 (y+4). Both ages increase by 4.<BR>\n" );
document.write( "x=3.5(y+4)-4=3.5 y+14-4<BR>\n" );
document.write( "x=3.5 y+10<BR>\n" );
document.write( "substitute into the first equation above<BR>\n" );
document.write( "3.5 y+10+y=64<BR>\n" );
document.write( "4.5 y=54=(9/2)y<BR>\n" );
document.write( "multiply both sides by 2<BR>\n" );
document.write( "9y=108<BR>\n" );
document.write( "y=12<BR>\n" );
document.write( "the son is 12 years old<BR>\n" );
document.write( "the mother is 52 years old<BR>\n" );
document.write( "in 4 years, he will be 16 and she 56.  56 is 3.5 times 16<BR>\n" );
document.write( "Four years ago, he was 8 and she was 48. ANSWER </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );