document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=90935>Question 90935</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, \r<BR>\n" );
document.write( "\n" );
document.write( "I need help with problem:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The length of a is 4 centimeters more than the width. If the length is increased by 8 centimeters and the width is decreased by 4 centimeters, the area will remain unchanged. Find the orignal  demensions of the rectangle. \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66019 by </B><A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><B>malakumar_kos@yahoo.com(315)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66019\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "The length of a is 4 centimeters more than the width. If the length is increased by 8 centimeters and the width is decreased by 4 centimeters, the area will remain unchanged. Find the orignal demensions of the rectangle\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "    Let the width of the rectangle be = x\r<BR>\n" );
document.write( "\n" );
document.write( "  Then the length of the rectangle   = x+4  cm \r<BR>\n" );
document.write( "\n" );
document.write( "     Therefore the Area of the rectangle A = x.(x+4) sq cms\r<BR>\n" );
document.write( "\n" );
document.write( "      Altered length of the rectangle = x+4+8 = x+12  cms\r<BR>\n" );
document.write( "\n" );
document.write( "       Altered width of the rectangle = x-4 cms\r<BR>\n" );
document.write( "\n" );
document.write( "      Area of the rectangle  = A = (x-4).(x+12)  sq cms\r<BR>\n" );
document.write( "\n" );
document.write( "      The Areas remain unaltered \r<BR>\n" );
document.write( "\n" );
document.write( "              x.(x+4) = (x-4).(x+12)\r<BR>\n" );
document.write( "\n" );
document.write( "               x^2+4x = x^2-4x+12x-48 <BR>\n" );
document.write( "              x^2-x^2+4x+4x-12x+48 = 0\r<BR>\n" );
document.write( "\n" );
document.write( "                    -12x+8x+48 = 0\r<BR>\n" );
document.write( "\n" );
document.write( "                    48 = 4x\r<BR>\n" );
document.write( "\n" );
document.write( "                    x = 48/4 = 12\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "        The original width = 12 cms \r<BR>\n" );
document.write( "\n" );
document.write( "        The original length  = 12+4 = 16 cms<BR>\n" );
document.write( "     </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );