document.write( "Question 1044782: Please help me solve this equation
\n" ); document.write( "Find the Parabola properties and graph
\n" ); document.write( "y^2+6x+6y=39\r
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\n" ); document.write( "\n" ); document.write( "Vertex:
\n" ); document.write( "Focus:
\n" ); document.write( "Directrix:
\n" ); document.write( "Axis of symmetry:
\n" ); document.write( "Endpoints of latus retum:
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Algebra.Com's Answer #660184 by MathLover1(20850)\"\" \"About 
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Find the Parabola properties and graph\r
\n" ); document.write( "\n" ); document.write( "given:
\n" ); document.write( "\"y%5E2%2B6x%2B6y=39\"\r
\n" ); document.write( "\n" ); document.write( "Vertex:
\n" ); document.write( "first write your equation in vertex form \"x-h=a%28y-k%29%5E2\" (since y squared) where \"h\" and \"k\" are \"x\" and \"y\" coordinates of the vertex
\n" ); document.write( "\"6x=-y%5E2-6y%2B39\"
\n" ); document.write( "\"x=-y%5E2%2F6-6y%2F6%2B39%2F6\"
\n" ); document.write( "\"x=-%281%2F6%29%28y%5E2%2B6y%29%2B13%2F2\"
\n" ); document.write( "\"x=-%281%2F6%29%28y%5E2%2B6y%2Bb%5E2%29-%28-1%2F6%29b%5E2%2B13%2F2\"
\n" ); document.write( "\"x=-%281%2F6%29%28y%5E2%2B6y%2B3%5E2%29-%28-1%2F6%293%5E2%2B13%2F2\"
\n" ); document.write( "\"x=-%281%2F6%29%28y%2B3%29%5E2-%28-1%2F6%299%2B13%2F2\"
\n" ); document.write( "\"x=-%281%2F6%29%28y%2B3%29%5E2%2B3%2F2%2B13%2F2\"
\n" ); document.write( "\"x=-%281%2F6%29%28y%2B3%29%5E2%2B16%2F2\"
\n" ); document.write( "\"x=-%281%2F6%29%28y%2B3%29%5E2%2B8\"
\n" ); document.write( "\"k=-3\" and \"h=8\"
\n" ); document.write( "vertex is at ( \"8\", \"-3\")\r
\n" ); document.write( "\n" ); document.write( "Since the value of a is negative, the parabola opens left.\r
\n" ); document.write( "\n" ); document.write( "Focus:
\n" ); document.write( "The focus of a parabola can be found by adding p to the x-coordinate h if the parabola opens left or right.
\n" ); document.write( "(\"h%2Bp\",\"k\")
\n" ); document.write( "Find p, the distance from the vertex to the focus.\r
\n" ); document.write( "\n" ); document.write( "Find \"p\", the distance from the vertex to a focus of the parabola by using the following formula.
\n" ); document.write( "\"p=1%2F4a\"
\n" ); document.write( "since \"a=-1%2F6\", we have
\n" ); document.write( "\"p=1%2F%284%28-1%2F6%29%29\"
\n" ); document.write( "\"p=-6%2F4\"
\n" ); document.write( "\"p=-3%2F2\"
\n" ); document.write( "(\"8-3%2F2\",\"-3\")\r
\n" ); document.write( "\n" ); document.write( "(\"16%2F2-3%2F2\",\"-3\")\r
\n" ); document.write( "\n" ); document.write( " ( \"13%2F2\", \"-3\")->focus\r
\n" ); document.write( "\n" ); document.write( "Directrix:
\n" ); document.write( "The directrix of a parabola is the vertical line found by subtracting p from the x-coordinate h
\n" ); document.write( "of the vertex if the parabola opens left or right.
\n" ); document.write( "\"x=h-p\"
\n" ); document.write( "\"x=8-%28-3%2F2%29\"
\n" ); document.write( "\"x=16%2F2%2B3%2F2\"
\n" ); document.write( "\"x+=+19%2F2\"\r
\n" ); document.write( "\n" ); document.write( "Axis of symmetry:
\n" ); document.write( "Find the axis of symmetry by finding the line that passes through the vertex and the focus.
\n" ); document.write( "vertex is at ( \"8\", \"-3\")
\n" ); document.write( " ( \"13%2F2\", \"-3\")->focus
\n" ); document.write( "and that will be \"y=-3\"\r
\n" ); document.write( "\n" ); document.write( "Endpoints of latus retum:\r
\n" ); document.write( "\n" ); document.write( "length of latus rectum = \"4p=4%2A%28-3%2F2%29=2%28-3%29=-6\"\r
\n" ); document.write( "\n" ); document.write( "endpoints of the latus rectum: (\"h%2Bp\",\"k-2p\") and (\"h%2Bp\",\"k%2B2p\")
\n" ); document.write( "since \"p=-3%2F2\", \"k=-3\" and \"h=8\" we have\r
\n" ); document.write( "\n" ); document.write( " (\"8%2B%28-3%2F2%29\",\"-3-2%28-3%2F2%29\") and (\"8%2B%28-3%2F2%29\",\"-3%2B2%28-3%2F2%29\")
\n" ); document.write( " (\"16%2F2-3%2F2\",\"-3%2B3\") and (\"16%2F2-3%2F2\",\"-3-3\")
\n" ); document.write( " (\"13%2F2\",\"0\") and (\"13%2F2\",\"-6\") \r
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