document.write( "Question 1044693: An artillery shell is fired with an initial velocity of 100 m/s at an angle of 30 degrees above the horizontal. Find:
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document.write( "a.) its position and velocity after 8 sec
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document.write( "b.) the time required to reach its maximum height
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document.write( "c.) The horizontal distance \n" );
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Algebra.Com's Answer #660179 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! An artillery shell is fired with an initial velocity of 100 m/s at an angle of 30 degrees above the horizontal. \n" ); document.write( "--- \n" ); document.write( "Using 10 m/sec/sec as gravity: \n" ); document.write( " Find: \n" ); document.write( "a.) its position and velocity after 8 sec \n" ); document.write( "The horizontal component = 100*cos(30) =~ 86.6 m/sec \n" ); document.write( "The vertical component = 100*sin(30) = 50 m/sec \n" ); document.write( "--- \n" ); document.write( "h(t) = -5t^2 + 50t \n" ); document.write( "h(8) = 80 meter AGL (height) \n" ); document.write( "--- \n" ); document.write( "The horizontal distance from the muzzle = 8*86.6 = 692.8 meters \n" ); document.write( "----- \n" ); document.write( "Horizontal speed is constant = 86.6 m/sec \n" ); document.write( "Vertical speed = 50 - 10t = -30 m/sec (descending) \n" ); document.write( "Its speed is the vector sum: \n" ); document.write( "= sqrt(86.6^2 + 30^2) =~ 91.65 m/sec \n" ); document.write( "===================== \n" ); document.write( "b.) the time required to reach its maximum height \n" ); document.write( "50/10 = 5 seconds \n" ); document.write( "========================= \n" ); document.write( "c.) The horizontal distance \n" ); document.write( "Flight time = 10 seconds \n" ); document.write( "H distance = 86.6*10 = 866 meters \n" ); document.write( " \n" ); document.write( " |