document.write( "Question 1044784: I need help i don't know how to solve Problem Solving like this :(
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document.write( "The base of an isosceles triangle is 8 m more than its altitude. If its area is 192 m^2, find the length of its sides. \n" );
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Algebra.Com's Answer #660169 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Area of a triangle is = 1/2(base x height) \n" ); document.write( "Make height (altitude) = x \n" ); document.write( "Base = x + 8 \n" ); document.write( "Area = 1/2(base x altitude) \n" ); document.write( "192 = 1/2(x(x + 8)) \n" ); document.write( "192 = 1/2(x^2 + 8x) \n" ); document.write( "Multiply both sides by 2 \n" ); document.write( "384 = x^2 + 8x \n" ); document.write( "Rearrange into ax^2 + bx + c form \n" ); document.write( "x^2 + 8x - 384 = 0 \n" ); document.write( "Factorise \n" ); document.write( "(x - 16)(x + 24) = 0 \n" ); document.write( "x + 24 = x = -24 (discount as -ve) \n" ); document.write( "x - 16 = 0 \n" ); document.write( "x = 16 \n" ); document.write( "Altitude = 16 m \n" ); document.write( "Base = 24 m \n" ); document.write( "........ \n" ); document.write( "Now we can work out the size of the two \n" ); document.write( "equal sides by dividing the base of 24 m \n" ); document.write( "into 2 lots of 12 m. \n" ); document.write( "We now have a right angled triangle \n" ); document.write( "with base of 12 m and an upright of \n" ); document.write( "16 m. \n" ); document.write( "To find the hypotenuse we use Pythagoras' Theorem. \n" ); document.write( "Namely:- Hypotenuse^2 = 12^2 + 16^2 \n" ); document.write( "Hypotenuse = √144 + 256 \n" ); document.write( "Hypotenuse = √400 \n" ); document.write( "Hypotenuse = 20 m \n" ); document.write( "............. \n" ); document.write( "Two equal sides = 20 m \n" ); document.write( "Base = 24 m \n" ); document.write( "Hope this helps :-) \n" ); document.write( " \n" ); document.write( " |