document.write( "Question 1044784: I need help i don't know how to solve Problem Solving like this :(
\n" ); document.write( "The base of an isosceles triangle is 8 m more than its altitude. If its area is 192 m^2, find the length of its sides.
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Algebra.Com's Answer #660166 by Alan3354(69443)\"\" \"About 
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I need help i don't know how to solve Problem Solving like this :(
\n" ); document.write( "The base of an isosceles triangle is 8 m more than its altitude. If its area is 192 m^2, find the length of its sides.
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\n" ); document.write( "Area = b*h/2 = 192
\n" ); document.write( "b*h = 384
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\n" ); document.write( "Find a pair of factors of 384 that differ by 8
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\n" ); document.write( "b = 24
\n" ); document.write( "h = 16
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\n" ); document.write( "The altitude forms 2 right triangles with sides of 12 & 16
\n" ); document.write( "The 2 equal sides are sqrt(12^2 + 16^2) = 20
\n" ); document.write( "--> sides are 20, 20 & 24
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