document.write( "Question 1044769: X+y+z=6
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Algebra.Com's Answer #660144 by ikleyn(52781) $\"\"$ $\"About$

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document.write( " x + y + z = 6,    (1)\r\n" );
document.write( " x - y + z = 2,    (2)\r\n" );
document.write( "2x + y - z = 1.    (3)\r\n" );
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document.write( "Distract equation (2) from equation (1) (both sides). You ill get\r\n" );
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document.write( "2y = 6-2 = 4  --->  y = 2.\r\n" );
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document.write( "Substitute y = 2 into equations (1) and (3). You will get\r\n" );
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document.write( " x + z =  4,        (4)    ( from (1) )\r\n" );
document.write( "2x - z = -1.        (5)    ( from (3) )\r\n" );
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document.write( "Add equations (4) and (5). You will get\r\n" );
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document.write( "3x = 3  --->  x = 1.\r\n" );
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document.write( "Now everybody can determine z. From (4), z = 4 - x = 4 - 1 = 3.\r\n" );
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document.write( "Answer. x=1, y=2, z=3.\r\n" );
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