document.write( "Question 90768: Solve the system by substitution.
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document.write( " x + y = 12
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document.write( " y = 2x\r
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document.write( "Solve the system by addition.
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document.write( " 5x – 3y = 13
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document.write( " 4x – 3y = 11
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Algebra.Com's Answer #66014 by malakumar_kos@yahoo.com(315)![]() ![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( " Solve the system by substitution. \n" ); document.write( "x + y = 12 \n" ); document.write( "y = 2x \r \n" ); document.write( "\n" ); document.write( "Solve the system by addition. \n" ); document.write( "5x – 3y = 13 \n" ); document.write( "4x – 3y = 11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 1) x+y = 12.....(1)\r \n" ); document.write( "\n" ); document.write( " y = 2x.......(2) \r \n" ); document.write( "\n" ); document.write( " substitute for y in (1)\r \n" ); document.write( "\n" ); document.write( " x+2x = 12 \n" ); document.write( " 3x = 12 or x = 12/3 = 4 \r \n" ); document.write( "\n" ); document.write( " y = 2*4 = 8\r \n" ); document.write( "\n" ); document.write( " The required solution is x = 4 and y = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 2)5x-3y =13.....(1)\r \n" ); document.write( "\n" ); document.write( " 4x-3y = 11.....(2)\r \n" ); document.write( "\n" ); document.write( " multiply (2) by -1 and add to (1)\r \n" ); document.write( "\n" ); document.write( " 5x-3y = 13 \n" ); document.write( " -4x+3y = -11 \n" ); document.write( " we get x = 2 because -3y & 3y gets cancelled\r \n" ); document.write( "\n" ); document.write( " substitute for x in (1)\r \n" ); document.write( "\n" ); document.write( " 5*2-3y = 13\r \n" ); document.write( "\n" ); document.write( " 10-13 = 3y \n" ); document.write( " 3y = -3 or y = -1\r \n" ); document.write( "\n" ); document.write( " The solution is x = 2 and y = -1 \n" ); document.write( " |