document.write( "Question 1044747: Darren drives to school in rush hour traffic and averages 32 mph. He returns home in mid-afternoon when there is less traffic and averages 48 mph. What is the distance between his home and school if the total traveling time is 1 hr 15 min? \n" ); document.write( "
Algebra.Com's Answer #660133 by ikleyn(52887)\"\" \"About 
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\n" ); document.write( "Darren drives to school in rush hour traffic and averages 32 mph. He returns home in mid-afternoon when there is less traffic
\n" ); document.write( "and averages 48 mph. What is the distance between his home and school if the total traveling time is 1 hr 15 min?
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document.write( "Let D be the distance under the question.\r\n" );
document.write( "Then your equation is\r\n" );
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document.write( "\"D%2F32+%2B+D+%2F48\" = \"1\"\"1%2F4\".\r\n" );
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document.write( "The first  addend in the left side is the time of driving at 32 mph.\r\n" );
document.write( "The second addend in the left side is the time of driving at 48 mph.\r\n" );
document.write( "The right side is the total traveling time, according to the condition.\r\n" );
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document.write( "To solve the equation, multiply both sides by 96, which is LCM of the denominators. You will get\r\n" );
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document.write( "3D + 2D = 120,\r\n" );
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document.write( "5D = 120,\r\n" );
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document.write( "D = \"120%2F5\" = 24.\r\n" );
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document.write( "Answer. The distance under the question is 24 miles.\r\n" );
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