document.write( "Question 1044752: I need help solving this conic in standard form\r
\n" ); document.write( "\n" ); document.write( "4x^2+4y^2-4x+2y-1=0
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Algebra.Com's Answer #660126 by ikleyn(52800)\"\" \"About 
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\n" ); document.write( "I need help solving this conic in standard form\r
\n" ); document.write( "\n" ); document.write( "4x^2+4y^2-4x+2y-1=0
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\n" ); document.write( "\n" ); document.write( "4x^2 + 4y^2 - 4x + 2y - 1 = 0
\n" ); document.write( "4x^2 - 4x + 4y^2 + 2y = 1
\n" ); document.write( "4[(x^2 - x + y^2 + (1/2)y] = 1
\n" ); document.write( "4(x-(1/2)x+1/4)+(y+(1/4)+(1/16))=1+1+(1/4). Complete the square, adding the constant to both sides.
\n" ); document.write( "4(x-(1/2))^2 + 4(y+(1/4))^2 = 9/4.
\n" ); document.write( "divide both sides by 4\r
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\n" ); document.write( "\n" ); document.write( "(x-1/2)^2 + (y+1/4)^2 = 9/16\r
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\n" ); document.write( "\n" ); document.write( "circle with center (1/2),-1/4) and radius 3/4.\r
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