document.write( "Question 1044752: I need help solving this conic in standard form\r
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document.write( "4x^2+4y^2-4x+2y-1=0 \n" );
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Algebra.Com's Answer #660126 by ikleyn(52800)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "I need help solving this conic in standard form\r \n" ); document.write( "\n" ); document.write( "4x^2+4y^2-4x+2y-1=0 \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4x^2 + 4y^2 - 4x + 2y - 1 = 0 \n" ); document.write( "4x^2 - 4x + 4y^2 + 2y = 1 \n" ); document.write( "4[(x^2 - x + y^2 + (1/2)y] = 1 \n" ); document.write( "4(x-(1/2)x+1/4)+(y+(1/4)+(1/16))=1+1+(1/4). Complete the square, adding the constant to both sides. \n" ); document.write( "4(x-(1/2))^2 + 4(y+(1/4))^2 = 9/4. \n" ); document.write( "divide both sides by 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-1/2)^2 + (y+1/4)^2 = 9/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "circle with center (1/2),-1/4) and radius 3/4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |