document.write( "Question 1044752: I need help solving this conic in standard form\r
\n" ); document.write( "\n" ); document.write( "4x^2+4y^2-4x+2y-1=0
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Algebra.Com's Answer #660122 by Boreal(15235)\"\" \"About 
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4x^2+4y^2-4x+2y-1=0
\n" ); document.write( "4x^2-4x+4y^2+2y=1
\n" ); document.write( "4[(x^2+x+y^2+(1/2)y]=1
\n" ); document.write( "4(x+(1/2)x+1/4)+(y+(1/4)+(1/16))=1+1+(1/4). Complete the square, adding the constant to both sides.
\n" ); document.write( "4(x+(1/2))^2+4(y+(1/4))^2=9/4.
\n" ); document.write( "divide both sides by 4
\n" ); document.write( "(x+1/2)^2+(y+1/4)^2=9/16
\n" ); document.write( "circle with center (-1/2),-1/4) and radius 3/4\r
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