document.write( "Question 1044743: The width of a swimming pool is 12 feet less than the pool's length. The area of the pool is 540 square feet. What are the dimensions of the pool?
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Algebra.Com's Answer #660104 by Boreal(15235)\"\" \"About 
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width=x
\n" ); document.write( "length=x+12, the width is 12 feet less, the length is 12 feet more. I could make length x and width x-12, but I'd rather deal with + than -. You get the same answer.
\n" ); document.write( "x(x+12)=540. LxW=area
\n" ); document.write( "x^2+12x-540=0
\n" ); document.write( "(x+30)(x-18)=0
\n" ); document.write( "x=-30, 18. Only the second answer makes sense
\n" ); document.write( "width is 18 feet and length is 30 feet.
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