document.write( "Question 1044710: In a triangle. The one angle of triangle is two times smallest an another three times smallest. Find all the angles of the triangle??? \n" ); document.write( "
Algebra.Com's Answer #660045 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let the smallest angle be \"alpha\"
\n" ); document.write( "if the angle \"beta\" of triangle is \"two\"\"+times\" smallest,than we have \"beta=2%2Aalpha\" and if \"gamma\" three times smallest we have \"gamma=3%2Aalpha\"\r
\n" ); document.write( "\n" ); document.write( "since the sum of all angles in triangle is \"180\"°, we have\r
\n" ); document.write( "\n" ); document.write( " \"alpha%2Bbeta%2Bgamma=180\"°........substitute \"beta\" and \"gamma\"\r
\n" ); document.write( "\n" ); document.write( " \"alpha%2B2%2Aalpha%2B3%2Aalpha=180\"°\r
\n" ); document.write( "\n" ); document.write( " \"6%2Aalpha=180\"°\r
\n" ); document.write( "\n" ); document.write( " \"alpha=180%2F6\"°\r
\n" ); document.write( "\n" ); document.write( "\"alpha=30\"°->the smallest angle\r
\n" ); document.write( "\n" ); document.write( "now find other two angles:\r
\n" ); document.write( "\n" ); document.write( " \"beta=2%2Aalpha\"-> \"beta=2%2A30\"°-> \"beta=60\"°
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\n" ); document.write( " \"gamma=3%2Aalpha\"->\"gamma=3%2A30\"°->\"gamma=90\"°\r
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