document.write( "Question 1044696: A football is kicked at an angle of 37 degrees with a velocity of 20 m/s. Calculate:
\n" ); document.write( "a.) Maximum height
\n" ); document.write( "b.) The time of travel before the ball hits the ground
\n" ); document.write( "c.) The range
\n" ); document.write( "d.) The velocity vector at the maximum height
\n" ); document.write( "e.) The acceleration vector at the maximum height
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Algebra.Com's Answer #660041 by Alan3354(69443)\"\" \"About 
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A football is kicked at an angle of 37 degrees with a velocity of 20 m/s.
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\n" ); document.write( "You didn't spec the Earth's gravitational acceleration.
\n" ); document.write( "I'll use 10 m/sec/sec
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\n" ); document.write( "Calculate:
\n" ); document.write( "a.) Maximum height
\n" ); document.write( "Vertical component Vv = 20*sin(37) =~ 12.036 m/sec
\n" ); document.write( "Flight time = 12.036*2/10 = 2.407 seconds
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\n" ); document.write( "h(t) = -5t^2 + 12.036t
\n" ); document.write( "Max is the vertex @ t = -b/2a = 12.036/10 = 1.2036 seconds
\n" ); document.write( "h(1.2036) = 7.243 meters Max height
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\n" ); document.write( "b.) The time of travel before the ball hits the ground
\n" ); document.write( "2.407 seconds
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\n" ); document.write( "c.) The range
\n" ); document.write( "Horizontal component = 20*cos(37) =~ 15.973 m/sec
\n" ); document.write( "range = 15.973*2.407 = 38.45 meters
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\n" ); document.write( "d.) The velocity vector at the maximum height
\n" ); document.write( "= Horizontal component at angle zero (no vertical speed)
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\n" ); document.write( "e.) The acceleration vector at the maximum height
\n" ); document.write( "= -5 m/sec/sec at all times until impact
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