document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1044700>Question 1044700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sqrt(2sqrt21+22) - sqrt21 = 1 explain this clearly pls </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #660030 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=660030\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> start with sqrt(2 * sqrt(21) + 22) - sqrt(21) = 1\r<BR>\n" );
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document.write( "add sqrt(21) to both sides of the equation to get:\r<BR>\n" );
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document.write( "sqrt(2 * sqrt(21) + 22) = 1 + sqrt(21)\r<BR>\n" );
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document.write( "square both sides of this equation to get:\r<BR>\n" );
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document.write( "2 * sqrt(21) + 22 = 1 + 2 * sqrt(21) + 21\r<BR>\n" );
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document.write( "simplify to get 2 * sqrt(21) + 22 = 22 + 2 * sqrt(21)\r<BR>\n" );
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document.write( "this can also be written as:\r<BR>\n" );
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document.write( "2 * sqrt(21) + 22 = 2 * sqrt(21) + 22\r<BR>\n" );
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document.write( "the equation is true which proves that the original equation is true.\r<BR>\n" );
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document.write( "you can also use your calculator to confirm.\r<BR>\n" );
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document.write( "in your scientific calculator, enter:\r<BR>\n" );
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document.write( "sqrt(2 * sqrt(21) + 22) - sqrt(21)\r<BR>\n" );
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document.write( "you will see that the result is equal to 1.\r<BR>\n" );
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document.write( "if your calculator doesn't do square roots, you can alternatively enter the expression as:\r<BR>\n" );
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document.write( "(2 * 21^(1/2) + 22)^(1/2) - 21^(1/2)\r<BR>\n" );
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document.write( "the result will also be equal to 1.\r<BR>\n" );
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document.write( "note that (1 + sqrt(21))^2 is equal to:\r<BR>\n" );
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document.write( "(1 + sqrt(21) * (1 + sqrt(21) which is equal to:\r<BR>\n" );
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document.write( "1 * 1 + 1 * sqrt(21) + sqrt(21) * 1 + sqrt(21) * sqrt(21) which is equal to:\r<BR>\n" );
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document.write( "1 + sqrt(21) + sqrt(21) + 21 which is equal to:\r<BR>\n" );
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document.write( "1 + 2 * sqrt(21) + 21 which is equal to:\r<BR>\n" );
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document.write( "22 + sqrt(21).\r<BR>\n" );
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document.write( "this is through use of the distributive law of multiplication.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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