document.write( "Question 1044581: Hi tutors here at algebra.com you've made my day happy. I just wanna ask this problem:\r
\n" ); document.write( "\n" ); document.write( "\" A car travels 60 miles in the same time that a car travelling 10 miles per hour faster travels 90 miles. What is the rate of each car?\"\r
\n" ); document.write( "\n" ); document.write( "Thanks for answering this problem
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Algebra.Com's Answer #659994 by MathTherapy(10557)\"\" \"About 
You can put this solution on YOUR website!
Hi tutors here at algebra.com you've made my day happy. I just wanna ask this problem:\r
\n" ); document.write( "\n" ); document.write( "\" A car travels 60 miles in the same time that a car travelling 10 miles per hour faster travels 90 miles. What is the rate of each car?\"\r
\n" ); document.write( "\n" ); document.write( "Thanks for answering this problem
\n" ); document.write( "
Let speed (rate) of slower car be S
\n" ); document.write( "Then speed (rate) of faster car = S + 10
\n" ); document.write( "Time slower car takes to cover 60 miles: \"60%2FS\"
\n" ); document.write( "Time faster car takes to cover 90 miles: \"90%2F%28S+%2B+10%29\"
\n" ); document.write( "We then get the following TIME equation: \"60%2FS+=+90%2F%28S+%2B+10%29\"
\n" ); document.write( "90S = 60(S + 10)------ Cross-multiplying
\n" ); document.write( "90S = 60S + 600
\n" ); document.write( "90S - 60S = 600
\n" ); document.write( "30S = 600
\n" ); document.write( "S, or speed (rate) of slower car = \"600%2F30\", or \"highlight_green%28matrix%281%2C2%2C+20%2C+mph%29%29\"
\n" ); document.write( "Add 10 to this speed (rate) to get speed (rate) of faster car. \n" ); document.write( "
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