document.write( "Question 1044643: 2^x 3^y 5^z=2000 where x,y,z are integers. Find the value of 2x+3y+5z \n" ); document.write( "
Algebra.Com's Answer #659967 by ikleyn(52790)\"\" \"About 
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\n" ); document.write( "2^x 3^y 5^z=2000 where x,y,z are integers. Find the value of 2x+3y+5z
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document.write( "1.  2000 = 2^4*3^0*5^3.\r\n" );
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document.write( "2.  If  \"2%5Ex%2A3%5Ey%2A5%5Ez\" = 2000, then x = 4,  y = 0,  z = 3.\r\n" );
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document.write( "3.  Having this, calculate 2x + 3y + 5z.\r\n" );
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