document.write( "Question 1044619: When Fritz drives to work his trip takes 36 minutes, but when he takes the train it takes 20 minutes. Find the distance Fritz travels to work if the train travels an average of 48 miles per hour faster than his driving. Assume that the train travels the same distance as the car. \n" ); document.write( "
Algebra.Com's Answer #659952 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let Fritz's rate be n. 36 minutes is 3/5 hr; 20 minutes equals 1/3 hour. So: \n" ); document.write( "3/5n=1/3(n+48) \n" ); document.write( "3/5n=1/3n+16 \n" ); document.write( "4/15n=16 \n" ); document.write( "n=60 \n" ); document.write( "3/5x60=36 miles to work. ☺☺☺☺ \n" ); document.write( " |