document.write( "Question 1044620: How many quarts of pure antifreeze must be added to 5 quarts of a 10​% antifreeze solution to obtain a 40​% antifreeze​ solution? \n" ); document.write( "
Algebra.Com's Answer #659927 by addingup(3677)\"\" \"About 
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Let x = amount of pure antifreeze required
\n" ); document.write( "Pure antifreeze is 100% = 1x
\n" ); document.write( ".10(5)+x = .40(x+5)
\n" ); document.write( ".5+x = .4x+2
\n" ); document.write( ".6x = 1.5
\n" ); document.write( "x = 2.5 gallons of pure antifreeze are needed
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