document.write( "Question 90867: Solve the following equations algebraically.\r
\n" ); document.write( "\n" ); document.write( "x3/2=27\r
\n" ); document.write( "\n" ); document.write( "3/4=1-3x-2/x+1
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Algebra.Com's Answer #65992 by malakumar_kos@yahoo.com(315)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( " Solve the following equations algebraically.
\n" ); document.write( "x3/2=27
\n" ); document.write( "3/4=1-3x-2/x+1\r
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\n" ); document.write( "\n" ); document.write( " 1) x^3/2 = 27\r
\n" ); document.write( "\n" ); document.write( " square both sides\r
\n" ); document.write( "\n" ); document.write( " (x^3/2)^2 = (27)^2
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\n" ); document.write( " (x)^3 = (3.3.3)^2
\n" ); document.write( " (x)^3 = (3^3)^2\r
\n" ); document.write( "\n" ); document.write( " (x)^3 = (3)^6\r
\n" ); document.write( "\n" ); document.write( " (x)^3 = (3^2)^3
\n" ); document.write( " (x)^3 = (9)^3 therefore x = 9\r
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\n" ); document.write( "\n" ); document.write( " 2) 3/4 = 1-3x-2/(x+1)\r
\n" ); document.write( "\n" ); document.write( " 3x+2/(x+1) = 1-3/4\r
\n" ); document.write( "\n" ); document.write( " 3x(x+1)+2/(x+1) = 4-3/4\r
\n" ); document.write( "\n" ); document.write( " 3x^2+3x+2/(x+1) = 1/4\r
\n" ); document.write( "\n" ); document.write( " 4(3x^2+3x+2) = 1(x+1)\r
\n" ); document.write( "\n" ); document.write( " 12x^2+12x+8 = x+1 \r
\n" ); document.write( "\n" ); document.write( " 12x^2+12x-x+8-1 = 0\r
\n" ); document.write( "\n" ); document.write( " 12x^2+11x+7 = 0 since it cannot be factorised use the formula\r
\n" ); document.write( "\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" where a = 12, b= 11 , c = 7\r
\n" ); document.write( "\n" ); document.write( " x = [-11+-sq rt (11^2-4.12.7)]/2.12\r
\n" ); document.write( "\n" ); document.write( " = [-11+- sq rt (121-336)]/24\r
\n" ); document.write( "\n" ); document.write( " = [-11+-Sq rt(-215)]/24 is the solution\r
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