document.write( "Question 1044597: A rational number is such that its denominator is greater than its numerator by constant K (K is not equal to 0).If the denominator is doubled the number obtained is again equal to original number.Find the rational number. \n" ); document.write( "

Algebra.Com's Answer #659903 by KMST(5328) $\"\"$ $\"About$

You can put this solution on YOUR website!
Either there is a typo, and the wording of the problem is not exactly as posted,
\n" ); document.write( "or this could be called a trick question.
\n" ); document.write( " $\"n\"$ = the numerator
\n" ); document.write( " $\"d=n%2BK\"$ = the denominator
\n" ); document.write( " $\"2%2Ad=2%28n%2BK%29\"$ = the denominator, doubled
\n" ); document.write( "
\n" ); document.write( "The original number is $\"n%2Fd\"$ .
\n" ); document.write( "The number with the denominator doubled (just the denominator) is $\"n%2F2d\"$ .
\n" ); document.write( "For both of those numbers to be equal, the only solution is $\"n=0\"$ .
\n" ); document.write( "That would make the original number $\"0%2FK=0\"$ ,
\n" ); document.write( "and the number with the denominator doubled would be $\"0%2F2K=0\"$ . \n" ); document.write( "

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