document.write( "Question 1044584: solve for x:
\n" ); document.write( "x^3+x^2-x=3
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Algebra.Com's Answer #659893 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
Try Rational Roots Theorem.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3%2Bx%5E2-x-3=0\"
\n" ); document.write( "Possible roots to check for are -3, -1, 1, 3; and you could expect possibly to find three roots.\r
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document.write( "-3    |    1   1   -1   -3\r\n" );
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document.write( "      |       -3   6    -15\r\n" );
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document.write( "          1   -2    5   -18\r\n" );
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document.write( "-1    |    1    1    -1    -3\r\n" );
document.write( "      |\r\n" );
document.write( "      |        -1     0     1\r\n" );
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document.write( "           1   0    -1     -2\r\n" );
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document.write( " 1    |    1    1    -1    -3\r\n" );
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document.write( "      |         1    2     1\r\n" );
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document.write( "           1    2    1    -2\r\n" );
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document.write( "  3    |     1    1    -1     -3\r\n" );
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document.write( "       |          3   12      33\r\n" );
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document.write( "            1     4    11     36\r\n" );
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\n" ); document.write( "No rational zeros found. A real zero seems to be between x values of 1 and 3 but finding it or them requires an approximation method.\r
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\n" ); document.write( "\n" ); document.write( "If you try a graphing tool, you will find a root or zero at close to \"x=1.358\". This will be the ONLY real root.
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