document.write( "Question 1044322: The average monthly income of a person for first eight months of a year exceeds that for first seven months of the year by 25. If he earna 1275 in eight month of the year find his average monthly income for the first eight months of the year \n" ); document.write( "
Algebra.Com's Answer #659869 by Boreal(15235)\"\" \"About 
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average = total/n
\n" ); document.write( "let average for 7 months =x
\n" ); document.write( "then x=total/7
\n" ); document.write( "when there are 8 months, the average is increased by 25 and the total increased by 1275, because that is what he earned.
\n" ); document.write( "so (x+25)=(total+1275)/8
\n" ); document.write( "7x=total; 8x=(8/7) total
\n" ); document.write( "8x+200=total +1275
\n" ); document.write( "8x=total+1075=(8/7) total
\n" ); document.write( "1075=(1/7) total, because (8/7) total-1 total =(1/7) total
\n" ); document.write( "total=$7525, and that is for 7 months
\n" ); document.write( "average for 7 months is $1075/month
\n" ); document.write( "total for 8 months is $8800, adding $1275.
\n" ); document.write( "average for 8 months is $8800/8=$1100, and that is $25 more than the 7 month average.
\n" ); document.write( "The answer is $1100 average monthly income for the first 8 months of the year
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