document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1044206>Question 1044206</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A group of people decided to go cross- country skiing and the group has decided to stop at a rest cabin located on the trail. What is the distance from the parking lot to the rest cabin, if they skied 3km west, 2km northwest, 3 km east and 4 km north to get to the cabin?\r<BR>\n" );
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document.write( "much much appreciated ..thanks for all your help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #659860 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=659860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the coordinate system.<BR>\n" );
document.write( "Start at the origin and go to (-3,0)<BR>\n" );
document.write( "Then go 2 km NW.  This is sqrt(2) unit to left and sqrt (2) unit up.  Sum of the squares is 2+2=4, and square root of 4 is 2.  The new coordinate is (-3-sqrt(2),sqrt(2))<BR>\n" );
document.write( "3 km east and the coordinate is (-sqrt(2), sqrt (2))<BR>\n" );
document.write( "4 km north and the final coordinate is (-sqrt(2), sqrt (2)+4))<BR>\n" );
document.write( "The distance is the sqrt of the sum of the squares, using the distance formula--subtracting 0 from each doesn't change that.<BR>\n" );
document.write( "sqrt (2+16+8 sqrt(2)+2)=sqrt(20+8 sqrt(2))<BR>\n" );
document.write( "numerically, that is 5.60 km </SPAN>\n" );
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