document.write( "Question 1044530: Prove that 7^(2n)+16n-1 is divisible by 64 \n" ); document.write( "
Algebra.Com's Answer #659853 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! Prove that 7^(2n)+16n-1 is divisible by 64 \n" ); document.write( ": \n" ); document.write( "we prove this by using mathematical induction \n" ); document.write( ": \n" ); document.write( "For n=1, we have 7^2 +16 -1 = 64 which is divisible by 64 \n" ); document.write( ": \n" ); document.write( "For n=k, we assume that 7^(2k)+16k-1 is divisible by 64 \n" ); document.write( ": \n" ); document.write( "We must check for n=k+1, is the statement true \n" ); document.write( ": \n" ); document.write( "7^(2(k+1)) +16(k+1) -1 = 49 * 7^2k + 16k +15 \n" ); document.write( ": \n" ); document.write( "we adjust this expression by adding and subtracting terms, that is \n" ); document.write( "we add 49*16k, -49 but we have to subtract 49*16k and -49 \n" ); document.write( ": \n" ); document.write( "we have the following \n" ); document.write( ": \n" ); document.write( "49*7^2k +16k +15 = 49*7^2k + 49*16k -49 -49*16k -49 +16k +15 = \n" ); document.write( ": \n" ); document.write( "49(7^2k +16k -1) - 49(16k-1) +16k +15 = \n" ); document.write( ": \n" ); document.write( "49(7^k +16k -1) - 48*16k +64 \n" ); document.write( ": \n" ); document.write( "all these terms are divisible by 64, so we are done :-) \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |