document.write( "Question 1044507: Use the logarithmic definition to find the derivative:
\n" ); document.write( "Y=(x+1)^x . Sqrt(x^2 + 4)
\n" ); document.write( "

Algebra.Com's Answer #659827 by Edwin McCravy(20059)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "\"y\"\"%22%22=%22%22\"\"%28x%2B1%29%5Ex\"\r\n" );
document.write( "\r\n" );
document.write( "\"ln%28y%29\"\"%22%22=%22%22\"\"ln%28+%28x%2B1%29%5Ex+%29\" \r\n" );
document.write( "\r\n" );
document.write( "\"ln%28y%29\"\"%22%22=%22%22\"\"x%2Aln%28x%2B1%29\"\r\n" );
document.write( "\r\n" );
document.write( "Use the formulas for the derivative of ln(u),\r\n" );
document.write( "are the formulas the derivative of uv and ln(u)\r\n" );
document.write( "on the right:\r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22%2Fy\"\"%22%22=%22%22\"\"x%2A%281%2F%28x%2B1%29%29%2Bln%28x%2B1%29%2A1\" \r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22%2Fy\"\"%22%22=%22%22\"\"x%2F%28x%2B1%29%2Bln%28x%2B1%29\"\r\n" );
document.write( "\r\n" );
document.write( "Multiply both sides by y\r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22\"\"%22%22=%22%22\"\"y%28x%2F%28x%2B1%29%2Bln%28x%2B1%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "Substitute for y on the right using the ORIGINAL equation\r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22\"\"%22%22=%22%22\"\"%28x%2B1%29%5Ex%2A%28x%2F%28x%2B1%29%2Bln%28x%2B1%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "------------------------------------\r\n" );
document.write( "\r\n" );
document.write( "\"y\"\"%22%22=%22%22\"\"sqrt%28x%5E2+%2B+4%29\"\r\n" );
document.write( "\r\n" );
document.write( "Square both sides:\r\n" );
document.write( "\r\n" );
document.write( "\"y%5E2\"\"%22%22=%22%22\"\"x%5E2+%2B+4\"\r\n" );
document.write( "\r\n" );
document.write( "\"2y%2A%22y%27%22\"\"%22%22=%22%22\"\"2x\"\r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22\"\"%22%22=%22%22\"\"%282x%29%2F%282y%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22\"\"%22%22=%22%22\"\"x%2Fy\"\r\n" );
document.write( "\r\n" );
document.write( "Substitute for y on the right using the ORIGINAL equation\r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22\"\"%22%22=%22%22\"\"x%2Fsqrt%28x%5E2+%2B+4%29\"\r\n" );
document.write( " \r\n" );
document.write( "\r\n" );
document.write( "That's the answer, but you were instructed to use \r\n" );
document.write( "natural logs.  So let's do it using natural logs:\r\n" );
document.write( "\r\n" );
document.write( "\"y\"\"%22%22=%22%22\"\"sqrt%28x%5E2+%2B+4%29\"\r\n" );
document.write( "\r\n" );
document.write( "Change the square root to the 1/2 power:\r\n" );
document.write( "\r\n" );
document.write( "\"y\"\"%22%22=%22%22\"\"%28x%5E2+%2B+4%29%5E%281%2F2%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"ln%28y%29\"\"%22%22=%22%22\"\"ln%28%28x%5E2+%2B+4%29%5E%281%2F2%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"ln%28y%29\"\"%22%22=%22%22\"\"expr%281%2F2%29%2Aln%28x%5E2+%2B+4%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22%2Fy\"\"%22%22=%22%22\"\"expr%281%2F2%29%2A%28%282x%29%2F%28x%5E2%2B4%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22%2Fy\"\"%22%22=%22%22\"\"expr%281%2Fcross%282%29%29%2A%28%28cross%282%29x%29%2F%28x%5E2%2B4%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22%2Fy\"\"%22%22=%22%22\"\"x%2F%28x%5E2%2B4%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "Multiply both sides by y\r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22\"\"%22%22=%22%22\"\"y%2A%28x%2F%28x%5E2%2B4%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "Substitute for y on the right using the ORIGINAL equation\r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22\"\"%22%22=%22%22\"\"sqrt%28x%5E2+%2B+4%29%2A%28x%2F%28x%5E2%2B4%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%22y%27%22\"\"%22%22=%22%22\"\"%28x%2Asqrt%28x%5E2+%2B+4%29%29%2F%28x%5E2%2B4%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "This is the same as the the answer we got when we did\r\n" );
document.write( "it by squaring both sides, but this way the denominator\r\n" );
document.write( "came out rationalized.  The two answers are equivalent.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );