document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=90926>Question 90926</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the line passing through each of the given pairs of points. Write your result in slope-intercept form. A) (-1, 3) and (4, -2); B) (2, -3) and (2, 4).\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65980 by </B><A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><B>malakumar_kos@yahoo.com(315)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( " Write the equation of the line passing through each of the given pairs of points. Write your result in slope-intercept form. A) (-1, 3) and (4, -2); B) (2, -3) and (2, 4). \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "   A) (-1,3)(4,-2)\r<BR>\n" );
document.write( "\n" );
document.write( "        The formula for finding the equation given two points is \r<BR>\n" );
document.write( "\n" );
document.write( "          y2-y1/y-y1 = x2-x1/x-x1\r<BR>\n" );
document.write( "\n" );
document.write( "          -2-3/y-3 = 4-(-1)/x-(-1)\r<BR>\n" );
document.write( "\n" );
document.write( "           -5/y-3 = 4+1/x+1\r<BR>\n" );
document.write( "\n" );
document.write( "           -5/y-3 = 5/x+1 \r<BR>\n" );
document.write( "\n" );
document.write( "        y-3 = -1(x+1)\r<BR>\n" );
document.write( "\n" );
document.write( "         y-3 = -x-1<BR>\n" );
document.write( "           y = -x-1+3   The required eq'n is y = -x+2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "   B)(2,-3)  (2,4)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "          The same eq'n is applied\r<BR>\n" );
document.write( "\n" );
document.write( "            y2-y1/y-y1 = x2-x1/x-x1 \r<BR>\n" );
document.write( "\n" );
document.write( "            4-(-3)/y-(-3) = 2-2/x-2\r<BR>\n" );
document.write( "\n" );
document.write( "             4+3/y+3 = 0/x-2\r<BR>\n" );
document.write( "\n" );
document.write( "              7/y+3 = 0   since R.H.S   is 0   eq'n is 0 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );