document.write( "Question 1044443: In a study of 420,009 cell phone users, 157 subjects developed brain cancer. Test the claim that cell phone users develop brain cancer at a rate that is different from the rate of 0.0340% for people who do not use cell phones. Because this issue has such great importance, use a 0.005 significance level. Use this information to answer the following questions.\r
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document.write( "B. What is the test statistic?
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document.write( "C. What is the P-vaule \n" );
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Algebra.Com's Answer #659781 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Ho:P=0.000340 \n" ); document.write( "Ha:P NE to 0.000340 \n" ); document.write( "alpha=0.005 \n" ); document.write( "test statistic is one-sample proportion (phat-p)/{sqrt(p*(1-p))/n} \n" ); document.write( "z=(phat-0.000340)/sqrt{(0.000340)(0.99966)/420009}; phat is 157/420,009=0.00037 \n" ); document.write( "SE=sqrt {(0.0003399)/420009}=0.00002845 \n" ); document.write( "Critical value is z>|2.576| \n" ); document.write( "Calculation is z= -(0.00003)/SE=-1.05 \n" ); document.write( "p-value is 0.23 \n" ); document.write( "Fail to reject Ho \n" ); document.write( " \n" ); document.write( " |