document.write( "Question 1044465: A company which supplies ready mix concrete receives, on average, 6 orders per day.
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document.write( "A) What is the probability that, on a given day:
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document.write( "(i) No orders are received?
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document.write( "(ii) No more than 2 orders are received?
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document.write( "(iii) At least 3 orders are received?
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document.write( "B) What is the probability that, on a given half-day, no orders are received?
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document.write( "C) What is the mean and standard deviation of orders received per day? \n" );
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Algebra.Com's Answer #659776 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Fits with poisson distribution where it is discrete, proportional to time, random, and could theoretically be infinite although unlikely. \n" ); document.write( "The poisson parameter is 6. \n" ); document.write( "p(0)=e^(-6)6^0/0! \n" ); document.write( "That is e^(-6)=0.0025 \n" ); document.write( "---------------------- \n" ); document.write( "no more than 2 is 0,1,2 \n" ); document.write( "p(1)=e^(-6)*6/1!=0.0149 \n" ); document.write( "p(2)=e^(-6)*6^2/2!=18*e^(-6)=0.0446 \n" ); document.write( "The sum of those 3 is 0.0620 \n" ); document.write( "--------------------------- \n" ); document.write( "At least 3 is 1-the above probability, since that is the complement. It will be 0.9380. \n" ); document.write( "------------------------------ \n" ); document.write( "At a given half day lambda=3 \n" ); document.write( "p(0)=e^(-3)=0.0498 \n" ); document.write( "Mean and variance are the same, and they are both the parameter lambda, here 6 orders for the mean and sqrt (6) or about 2.45 orders for sd. \n" ); document.write( " \n" ); document.write( " |