document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1044481>Question 1044481</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hey! So I know you have to use the distance formula and everything on this problem but it's been a while since I've had to use it. The problem is: two cars travel in opposite directions. One travels 20mph slower than the other. After 3 hours, they are 270 miles apart. How fast is each car going? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #659763 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=659763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The way I do this is that the cars are going in opposite directions and after 3 hours they are 270 miles apart.<BR>\n" );
document.write( "270 miles/3 hours=90 miles/ hour is the separation speed and that is the combined speed of both cars.  Therefore,<BR>\n" );
document.write( "car a+car b=90<BR>\n" );
document.write( "but car a -20=car b, which means that car b is 20 mph slower than car a<BR>\n" );
document.write( "substitute into the first equation.<BR>\n" );
document.write( "car a+car a-20=90<BR>\n" );
document.write( "2 car a=110<BR>\n" );
document.write( "car a=55 mph<BR>\n" );
document.write( "car b=55-20, or 35 mph<BR>\n" );
document.write( "check<BR>\n" );
document.write( "In 3 hours, car a has gone 55*3=165 miles<BR>\n" );
document.write( "car b has gone 35*3=105 miles<BR>\n" );
document.write( "They add to 270 miles </SPAN>\n" );
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