document.write( "Question 1044426: A city has 3200 houses out of which 3/4 are older than 100 years. if 1/3 of these old houses are renovated and an additional 800 new houses were built, what is the percentage of houses that are not renovated?
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Algebra.Com's Answer #659731 by robertb(5830)\"\" \"About 
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Of the 3,200 houses, \"%283%2F4%29%2A3200+=+2400\" are older than 100 years.\r
\n" ); document.write( "\n" ); document.write( "\"%281%2F3%29%2A2400+=+800\" were renovated, and so 2,400 - 800 = 1,600 stayed unrenovated. \r
\n" ); document.write( "\n" ); document.write( "800 new houses built means that there are now 4,000 houses in total.\r
\n" ); document.write( "\n" ); document.write( "===> \"1600%2F4000+=+2%2F5\", or 40% of the houses are not renovated.
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