document.write( "Question 1044343: An inverted regular pyramid whose square base has an area of 16 square units and a height of 6 units contains water with a depth of 3 units. If the said pyramid is set upright, how high is the water level? \n" ); document.write( "
Algebra.Com's Answer #659616 by KMST(5328)![]() ![]() You can put this solution on YOUR website! This problem has numbers and specifications that are not really needed. \n" ); document.write( "If an inverted pyramid of any shape and size \n" ); document.write( "is filled with water to half of its height, \n" ); document.write( "the height of the water after turning it upright is \n" ); document.write( " \n" ); document.write( "In the case of a container of height 6 units, originally filled to a depth of \n" ); document.write( "the final water height is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The container is a pyramid that has a height \n" ); document.write( "The part originally filled with water is a similar pyramid. \n" ); document.write( "Its height is \n" ); document.write( "The original water-filled pyramid is a smaller version of the container pyramid, \n" ); document.write( "scaled down by a factor of \n" ); document.write( "For scaled up or down objects, if the ratio of corresponding length is \n" ); document.write( "If you know one ratio you can find the other. \n" ); document.write( "So, the volume of that original water-filled pyramid is \n" ); document.write( "When the container pyramid is set upright, the water still fills \n" ); document.write( "but now the water is against the base of the container pyramid. \n" ); document.write( "Above the water there is an air-filled pyramid with volume \n" ); document.write( "The height of that pyramid is \n" ); document.write( "The height of the water is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |