document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13066>Question 13066</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two girls are 60 miles apart.  Leaving at the same time, mary will travel 21 miles/hr and  sally will travel 15miles/hr. when will the meet.  Please help with the formula.<BR>\n" );
document.write( "PL </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6596 by </B><A HREF=/tutors/aboutme.mpl?userid=glabow><B>glabow(165)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=glabow><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume you know where they will meet and call it M. How long does it take Mary to get to M? The answer is 21 mi/hr times x hours. So, we have <BR>\n" );
document.write( "21x = M<BR>\n" );
document.write( "How long does it take Sally to get to M? The answer is that she must travel the distance that takes her to M starting at 60 mi. And that is 60-M. So, we have<BR>\n" );
document.write( "15x = 60-M<BR>\n" );
document.write( "Substituting the value of M from the first equation into the second we get<BR>\n" );
document.write( "15x = 60 - 21x<BR>\n" );
document.write( "36x = 60<BR>\n" );
document.write( "x = 5/3<BR>\n" );
document.write( "This says that after 5/3 of an hour Mary will have travelled 35 miles (21 x 5/3) and<BR>\n" );
document.write( "Sally will have travelled 25 miles (15 x 5/3).<BR>\n" );
document.write( "Checking: 35 miles + 25 miles = 60 miles.<BR>\n" );
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