document.write( "Question 1044204: Points A, B and C are collinear. Point B is the midpoint of the line segment AC. Point D is a point not collinear with the other points for which DA=DB and DB=BC=10. Then DC is:
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document.write( "A) 20/✔️3
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document.write( "B) 10✔️2
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document.write( "C) 10✔️3
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document.write( "D) 20
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document.write( "E) 40/✔️3 \n" );
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Algebra.Com's Answer #659480 by robertb(5830)![]() ![]() You can put this solution on YOUR website! Let y = distance of point D from segment AB.\r \n" ); document.write( "\n" ); document.write( "Then \n" ); document.write( "\n" ); document.write( "===> \n" ); document.write( "\n" ); document.write( "But also the distance of the foot of the perpendicular bisector of AB from point C is 5+10 = 15 units. Hence,\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "===> \n" ); document.write( "\n" ); document.write( "===> |