document.write( "Question 1026091: A furniture shop refinishes tables. Employees use one of two methods to refinish each table. Method I takes 2 hours and the material costs $8. Method II takes 2.5 hours, and the material costs $6. Next week, they plan to spend 333 hours in labor and $940 in material for refinishing tables. How many tables should they plan to refinish with each method \n" ); document.write( "
Algebra.Com's Answer #659451 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let m and n represent method I and method II, respectively. Then: \n" ); document.write( "2m+2.5n=333 \n" ); document.write( "8m+6n=940 \n" ); document.write( "Then: \n" ); document.write( "8m+10n=1332 \n" ); document.write( "4n=392 \n" ); document.write( "n=98 \n" ); document.write( "m=44 \n" ); document.write( "They can refinish 44 tables using method I, and 98 using method II. ☺☺☺☺ \n" ); document.write( " \n" ); document.write( " |