document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1044177>Question 1044177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the system\r<BR>\n" );
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document.write( "x-3y=2\r<BR>\n" );
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document.write( "-x+2y=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #659442 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=659442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-3y=2<BR>\n" );
document.write( "-x+2y=0.  When you have two equations where one variable is exactly opposite in both equations, you add them and that variable disappears.<BR>\n" );
document.write( "When you add these two, you get<BR>\n" );
document.write( "-y=2<BR>\n" );
document.write( "y=-2<BR>\n" );
document.write( "substitute into one equation to get x<BR>\n" );
document.write( "x-(-6)=2<BR>\n" );
document.write( "x+6=-2<BR>\n" );
document.write( "x=-4<BR>\n" );
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document.write( "check by trying both in the other equation -(-4)+(2)(-2)=0<BR>\n" );
document.write( "checks<BR>\n" );
document.write( "(-4,-2) </SPAN>\n" );
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