document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1044109>Question 1044109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A (9,5) and B (5,-9) are two points on a circle centered at the origin.\r<BR>\n" );
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document.write( "a) Determine an equation for the circle.\r<BR>\n" );
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document.write( "b) Determine the midpoint C of chord AB.\r<BR>\n" );
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document.write( "c) Show that the right bisector of chord AB passes through the centre of the circle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #659391 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=659391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2+y^2=r^2<BR>\n" );
document.write( "81+25=106 with point 1 and point 2.r=10.3<BR>\n" );
document.write( "x^2+y^2=106 is the equation of the circle<BR>\n" );
document.write( "The chord\"s midpoint is the midpoint of each x and each y, or (7,-2)<BR>\n" );
document.write( "The equation of the line that makes the chord has slope (-9-5)/(5-9)=-14/-4=7/2<BR>\n" );
document.write( "the point slope formula is y+9=(7/2)(x-5), or y=(7/2)x-53/2.<BR>\n" );
document.write( "The perpendicular bisector must have- slope -2/7, the negative reciprocal.<BR>\n" );
document.write( "It's equation is y+2=(-2/7)(x-7), or y=(-2/7)x, and this goes through (0,0)<BR>\n" );
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