document.write( "Question 1044135: Please help me solve this, im confused\r
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\n" ); document.write( "\n" ); document.write( "The difference between the first number and two times the second
\n" ); document.write( " number is -54, while the sum of three times the first number plus
\n" ); document.write( " twice the second is 94. What is the first number?
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Algebra.Com's Answer #659390 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
let a = the 1st number
\n" ); document.write( "let b = the 2nd number
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\n" ); document.write( "Write an equation fore each statement
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\n" ); document.write( "The difference between the first number and two times the second
\n" ); document.write( "number is -54,
\n" ); document.write( "a - 2b = -54
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\n" ); document.write( "while the sum of three times the first number plus twice the second is 94.
\n" ); document.write( "3a + 2b = 94
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\n" ); document.write( "use elimination on these two equation
\n" ); document.write( " a - 2b = -54
\n" ); document.write( "3a + 2b = 94
\n" ); document.write( "--------------Addition eliminates b, find a
\n" ); document.write( "4a = +40
\n" ); document.write( "a = 40/4
\n" ); document.write( "a = 10
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\n" ); document.write( "Use the 1st equation to find b
\n" ); document.write( "10 - 2b = -54
\n" ); document.write( "-2b = -54 - 10
\n" ); document.write( "-2b = -64
\n" ); document.write( "b = -64/-2
\n" ); document.write( "b = +32
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\n" ); document.write( "Check solutions in the 2nd equation
\n" ); document.write( "3(10) + 2(32) = 94
\n" ); document.write( "30 + 64 = 94\r
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