document.write( "Question 1044135: Please help me solve this, im confused\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "The difference between the first number and two times the second
\n" );
document.write( " number is -54, while the sum of three times the first number plus
\n" );
document.write( " twice the second is 94. What is the first number? \n" );
document.write( "
Algebra.Com's Answer #659390 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let a = the 1st number \n" ); document.write( "let b = the 2nd number \n" ); document.write( ": \n" ); document.write( "Write an equation fore each statement \n" ); document.write( ": \n" ); document.write( "The difference between the first number and two times the second \n" ); document.write( "number is -54, \n" ); document.write( "a - 2b = -54 \n" ); document.write( ": \n" ); document.write( "while the sum of three times the first number plus twice the second is 94. \n" ); document.write( "3a + 2b = 94 \n" ); document.write( ": \n" ); document.write( "use elimination on these two equation \n" ); document.write( " a - 2b = -54 \n" ); document.write( "3a + 2b = 94 \n" ); document.write( "--------------Addition eliminates b, find a \n" ); document.write( "4a = +40 \n" ); document.write( "a = 40/4 \n" ); document.write( "a = 10 \n" ); document.write( ": \n" ); document.write( "Use the 1st equation to find b \n" ); document.write( "10 - 2b = -54 \n" ); document.write( "-2b = -54 - 10 \n" ); document.write( "-2b = -64 \n" ); document.write( "b = -64/-2 \n" ); document.write( "b = +32 \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Check solutions in the 2nd equation \n" ); document.write( "3(10) + 2(32) = 94 \n" ); document.write( "30 + 64 = 94\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |