document.write( "Question 90881: Please assist me with this problem. Thanks!
\n" ); document.write( "Write an equation of a line which is parallel to 5x + 2y = 4 and passes through the point (1,0).
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Algebra.Com's Answer #65938 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


\"5x%2B2y=4\" Start with the given equation


\"5x%2B2y-5x=4-5x\" Subtract 5x from both sides


\"2y=-5x%2B4\" Simplify


\"%282y%29%2F%282%29=%28-5x%2B4%29%2F%282%29\" Divide both sides by 2 to isolate y


\"y+=+%28-5x%29%2F%282%29%2B%284%29%2F%282%29\" Break up the fraction on the right hand side


\"y+=+%28-5%2F2%29x%2B2\" Reduce and simplify


The original equation \"5x%2B2y=4\" (standard form) is equivalent to \"y+=+%28-5%2F2%29x%2B2\" (slope-intercept form)


The equation \"y+=+%28-5%2F2%29x%2B2\" is in the form \"y=mx%2Bb\" where \"m=-5%2F2\" is the slope and \"b=2\" is the y intercept.



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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"-5%2F2\" (its from the slope of \"y=%28-5%2F2%29%2Ax%2B2\" which is also \"-5%2F2\").\n" ); document.write( "Also since the unknown line goes through (1,0), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-0=%28-5%2F2%29%2A%28x-1%29\" Plug in \"m=-5%2F2\", \"x%5B1%5D=1\", and \"y%5B1%5D=0\"
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\n" ); document.write( " \"y-0=%28-5%2F2%29%2Ax%2B%285%2F2%29%281%29\" Distribute \"-5%2F2\"
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\n" ); document.write( " \"y-0=%28-5%2F2%29%2Ax%2B5%2F2\" Multiply
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\n" ); document.write( " \"y=%28-5%2F2%29%2Ax%2B5%2F2%2B0\"Add \"0\" to both sides to isolate y
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\n" ); document.write( " \"y=%28-5%2F2%29%2Ax%2B5%2F2%2B0%2F2\" Make into equivalent fractions with equal denominators
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\n" ); document.write( " \"y=%28-5%2F2%29%2Ax%2B5%2F2\" Combine the fractions
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\n" ); document.write( " \"y=%28-5%2F2%29%2Ax%2B5%2F2\" Reduce any fractions
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\n" ); document.write( " So the equation of the line that is parallel to \"y=%28-5%2F2%29%2Ax%2B2\" and goes through (\"1\",\"0\") is \"y=%28-5%2F2%29%2Ax%2B5%2F2\"
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\n" ); document.write( " So here are the graphs of the equations \"y=%28-5%2F2%29%2Ax%2B2\" and \"y=%28-5%2F2%29%2Ax%2B5%2F2\"
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\n" ); document.write( " graph of the given equation \"y=%28-5%2F2%29%2Ax%2B2\" (red) and graph of the line \"y=%28-5%2F2%29%2Ax%2B5%2F2\"(green) that is parallel to the given graph and goes through (\"1\",\"0\")
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