document.write( "Question 1044110: The centre of a circle has coordinates (0,0) One end of a diameter is located at (7,-2)\r
\n" ); document.write( "\n" ); document.write( "a) What are the coordinates of the other endpoint of this diameter? \r
\n" ); document.write( "\n" ); document.write( "b) What is the equation of the circle?
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Algebra.Com's Answer #659363 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
(\"0\", \"0\") is the midpoint of the diameter. Use the midpoint formula to determine the other end point.\r
\n" ); document.write( "\n" ); document.write( "\"0=%28x%2B7%29%2F2\"=>\"x%2B7=0\"=>\"x=-7\"
\n" ); document.write( "\"0=%28y%2B%28-2%29%29%2F2\"=>\"y-2=0\"=>\"y=2\"
\n" ); document.write( "the other endpoint is at (\"-7\",\"2\")\r
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\n" ); document.write( "\n" ); document.write( "b)
\n" ); document.write( "recall standard formula for a circle:
\n" ); document.write( "\"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\", where \"r\" being the radius , \"h\" and \"k\" are \"x\" and \"y\" coordinates of the center\r
\n" ); document.write( "\n" ); document.write( "since the center is at origin, \"h=0\" and \"k=0\" and your formula is\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+y%5E2+=+r%5E2\"\r
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\n" ); document.write( "\n" ); document.write( " the length of the radius is \"1%2F2\" of the distance between two endpoints \r
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\n" ); document.write( "\n" ); document.write( "\"r=sqrt%28+%28x1-x2%29%5E2%2B%28y1-y2%29%5E2%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"r=sqrt%28+%287-%28-7%29%29%5E2%2B%28-2-2%29%5E2%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"r=sqrt%28+%287%2B7%29%5E2%2B%28-2-2%29%5E2%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"r=sqrt%28+14%5E2%2B%28-4%29%5E2%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"r=sqrt%28+196%2B16%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"r=sqrt%28+212%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"r=sqrt%28+53%2A4%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"r=2sqrt%28+53%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"r=sqrt%28+53%29\".......exact solution
\n" ); document.write( "so, your equation is:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+y%5E2+=+%28sqrt%28+53%29%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x%5E2+%2B+y%5E2+=+53%29\"\r
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