document.write( "Question 90879This question is from textbook Beginning Algebra
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document.write( ": Solve by completing the square: 4x^2 + 2x - 3 = 0\r
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document.write( "4x^2 + 2x = 3
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document.write( "x^2 + 2/4x = 3/4
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document.write( "Square one-half of the of the x-coefficient and then add it to both sides
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document.write( "1/2 of 2/4 = 1/4^2 = 1/16
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document.write( "x^2 + 2/4x + 1/16 = 3/4 + 1/16
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document.write( "(x-1/4)^2 = 13/16
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document.write( "x - 1/4 = +/- radical 13 over radical 16
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document.write( "x - 1/4 = +/- radical 13 over 4
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document.write( "x = 1/4 +/- radical 13 over 4
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document.write( "x = 1 +/- radical 13 over 4 \r
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document.write( "Any help is appreciated. \n" );
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Algebra.Com's Answer #65936 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve by completing the square: 4x^2 + 2x - 3 = 0\r \n" ); document.write( "\n" ); document.write( "4x^2 + 2x = 3 \n" ); document.write( "x^2 + 2/4x = 3/4 \n" ); document.write( "Square one-half of the of the x-coefficient and then add it to both sides \n" ); document.write( "1/2 of 2/4 = 1/4 \n" ); document.write( "x^2 + (1/2)x + (1/4)^2 = 3/4 + (1/4)^2 \n" ); document.write( "(x-1/4)^2 = 13/16 \n" ); document.write( "(x-1/4) = +-[sqrt13]/4 \n" ); document.write( "x = [1+sqrt13]/4 or x = [1-sqrt13]/4 \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |