document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1044104>Question 1044104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Francois rolls a pair of dice.<BR>\n" );
document.write( "A.) what is the probability that he will roll a total of 9 on one roll? \r<BR>\n" );
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document.write( "B.) what is the probability that he will roll a 5 followed by a 2 on two consecutive rolls?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #659348 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=659348\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A) using a pair of dice, the possible nines are<BR>\n" );
document.write( "(3,6), (6,3) (4, 5), (5, 4)<BR>\n" );
document.write( "There are 36 possible outcomes, therefore<BR>\n" );
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document.write( "Probability of rolling a total of 9 = 4/36 = 1/9<BR>\n" );
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document.write( "B) using a pair of dice, <BR>\n" );
document.write( "(5,2), (5,2)<BR>\n" );
document.write( "Probability of rolling (5,2) on two consecutive rolls is (1/36) * (1/36) =  1/1296<BR>\n" );
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