document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1044099>Question 1044099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There were 38 nickels, dimes and quarters whose total value came to $4.00. How many coins of each kind were there if there were twice as many dimes as nickels?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #659337 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=659337\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d be dimes, n be nickels, q be quarters. Then<BR>\n" );
document.write( "d+n+q=38<BR>\n" );
document.write( "d=2n, so 3n+q=38<BR>\n" );
document.write( ".05n+.1(2n)+.25q=4<BR>\n" );
document.write( ".25n+.25q=4<BR>\n" );
document.write( "3n+q=38<BR>\n" );
document.write( "n+q=16<BR>\n" );
document.write( "2n=22<BR>\n" );
document.write( "n=11<BR>\n" );
document.write( "d=22<BR>\n" );
document.write( "q=5<BR>\n" );
document.write( "There are 11 nickels, 22 dimes, and 5 quarters, totaling $4.00 . &#9786;&#9786;&#9786;&#9786;<BR>\n" );
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