document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1044027>Question 1044027</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What multiplies to -90 and adds to -4? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #659249 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=659249\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> xy=-90<BR>\n" );
document.write( "x+y=-4<BR>\n" );
document.write( "y=-90/x<BR>\n" );
document.write( "x+(-90/x)=-4<BR>\n" );
document.write( "multiply all by x<BR>\n" );
document.write( "x^2-90=-4x<BR>\n" );
document.write( "x^2+4x-90=0\r<BR>\n" );
document.write( "\n" );
document.write( "x=(1/2)(-4+/- sqrt(16+360));sqrt 376=19.39<BR>\n" );
document.write( "x=(1/2)(-4-19.39) or -11.7; y=(1/2)(-4+19.39)=7.7<BR>\n" );
document.write( "The exact value is -2+(1/2)sqrt(376) and -2-(1/2) sqrt (376).  That product is 4-(1/4)(376)=-90<BR>\n" );
document.write( "and the sum is -4.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );