document.write( "Question 1043957: Amacha leaves her office at 8:00 am and drives to
\n" ); document.write( "a client's office at an average rate of 80kph.She
\n" ); document.write( "spends 2 hours in meeting,takes a 1 hour lunch
\n" ); document.write( "and returns to her own office,driving at an average
\n" ); document.write( "of 60kph.If she arrives back at her office at 3:00 pm,
\n" ); document.write( "how far apart are the two offices?
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Algebra.Com's Answer #659184 by ikleyn(52777)\"\" \"About 
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\n" ); document.write( "Amacha leaves her office at 8:00 am and drives to
\n" ); document.write( "a client's office at an average rate of 80kph. She
\n" ); document.write( "spends 2 hours in meeting,takes a 1 hour lunch
\n" ); document.write( "and returns to her own office,driving at an average
\n" ); document.write( "of 60kph.If she arrives back at her office at 3:00 pm,
\n" ); document.write( "how far apart are the two offices?
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document.write( "Amacha spent driving 7 hours - 3 hours = 4 hours.\r\n" );
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document.write( "Led D be the distance between the offices.\r\n" );
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document.write( "Then you have this equation for the unknown D\r\n" );
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document.write( "\"D%2F80+%2B+D%2F60\" = 4,   (1)\r\n" );
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document.write( "where 4 = 4 hours is the total driving time.\r\n" );
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document.write( "To solve (1), multiply both sides by the Least Common Denominator 240. You will have\r\n" );
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document.write( "3D + 4D = 4*240,   or   7D = 960.\r\n" );
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document.write( "Hence, D = \"960%2F7\" = 137.14 miles.\r\n" );
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