document.write( "Question 1043957: Amacha leaves her office at 8:00 am and drives to
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document.write( "a client's office at an average rate of 80kph.She
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document.write( "spends 2 hours in meeting,takes a 1 hour lunch
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document.write( "and returns to her own office,driving at an average
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document.write( "of 60kph.If she arrives back at her office at 3:00 pm,
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document.write( "how far apart are the two offices? \n" );
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Algebra.Com's Answer #659184 by ikleyn(52777)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Amacha leaves her office at 8:00 am and drives to \n" ); document.write( "a client's office at an average rate of 80kph. She \n" ); document.write( "spends 2 hours in meeting,takes a 1 hour lunch \n" ); document.write( "and returns to her own office,driving at an average \n" ); document.write( "of 60kph.If she arrives back at her office at 3:00 pm, \n" ); document.write( "how far apart are the two offices? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Amacha spent driving 7 hours - 3 hours = 4 hours.\r\n" ); document.write( "\r\n" ); document.write( "Led D be the distance between the offices.\r\n" ); document.write( "\r\n" ); document.write( "Then you have this equation for the unknown D\r\n" ); document.write( "\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |