document.write( "Question 1043957: Amacha leaves her office at 8:00 am and drives to
\n" ); document.write( "a client's office at an average rate of 80kph.She
\n" ); document.write( "spends 2 hours in meeting,takes a 1 hour lunch
\n" ); document.write( "and returns to her own office,driving at an average
\n" ); document.write( "of 60kph.If she arrives back at her office at 3:00 pm,
\n" ); document.write( "how far apart are the two offices?
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Algebra.Com's Answer #659183 by Alan3354(69443)\"\" \"About 
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Amacha leaves her office at 8:00 am and drives to
\n" ); document.write( "a client's office at an average rate of 80kph.She
\n" ); document.write( "spends 2 hours in meeting,takes a 1 hour lunch
\n" ); document.write( "and returns to her own office,driving at an average
\n" ); document.write( "of 60kph.If she arrives back at her office at 3:00 pm,
\n" ); document.write( "how far apart are the two offices?
\n" ); document.write( "--------
\n" ); document.write( "She spends 4 hours driving.
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\n" ); document.write( "Avg speed for the round trip = 2*80*60/(80+60) = 480/7 km/hr
\n" ); document.write( "RT distance = 4*480/7 km
\n" ); document.write( "Each way = 960/7 kms
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