document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043951>Question 1043951</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A sum of 6000 is invested, part of it at 9% interest and the remainder at 11%. If the interest earned by the 9% investment is 160 less than the interest earned by the 11% investment, find the amount invested at each rate<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #659174 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=659174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.09x = 0.11(6000-x)-160<BR>\n" );
document.write( "0.09x = 660-0.11x-160<BR>\n" );
document.write( "0.20x = 500<BR>\n" );
document.write( "x = 2500 this is the amount invested at 9%<BR>\n" );
document.write( "6000-2500 = 3500 is the amount invested at 11%<BR>\n" );
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document.write( "check:<BR>\n" );
document.write( "0.11*3500 = 385<BR>\n" );
document.write( "0.09*2500 = 225<BR>\n" );
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document.write( "Difference: 160 Correct<BR>\n" );
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document.write( "John<BR>\n" );
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